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5x^2-69x+170=0
a = 5; b = -69; c = +170;
Δ = b2-4ac
Δ = -692-4·5·170
Δ = 1361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-\sqrt{1361}}{2*5}=\frac{69-\sqrt{1361}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+\sqrt{1361}}{2*5}=\frac{69+\sqrt{1361}}{10} $
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